Aball is thrown straight up into the air with a speed of 10 m/s . if the ball has a mass of 0.3 kg how high does the ball go ?

= 5.102 m

The total energy, i.e. sum of kinetic and potential energy, is constant.

That is; E = KE + PE

Initially, PE = 0 and KE = 1/2 mv^2

At maximum height, velocity=0, thus, KE = 0 and PE = mgh

Since, total energy is constant (KE converts to PE when the ball is rising).

Therefore, KE = PE

or, 1/2 mv^2 = mgh

or, h = v^2 /2g

        = 10^2 / (2x9.8)

        = 5.102 m