You exert a 100-n pull on the end of a spring. when you increase the force by 20% to 120 n, the spring's length increases 9.0 cm beyond its original stretched position. part a: what is the spring constant of the spring? (i got k = 222 n/m)

part b: what is its original displacement? (i can't really figure this part out)

A) 222 N/m

Explanation:

Hook's law gives us the relationship between force (F), displacement with respect to the original length (x) and spring's constant (k):

In this part of the problem, we have:

F = 120 N - 100 N = 20 N is the new force applied

x = 9.0 cm = 0.09 m is the displacement relative to the initial stretched position

Solving the equation for k, we find the spring constant

B) 45 cm

We can use Hook's law also for this part of the exercise:

where this time we have

F = 100 N (the original pull applied)

k = 222 N/m

Solving the equation for x, we find the original displacement:

the independent variable, the one that is intentionally manipulated, is whether or not the car hits the barrier.

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don't remove my answer im trying my best to answer them

explanation: