Some pacemakers employ magnetic reed switches to enable doctors to change their mode of operation without surgery. a typical reed switch can be switched from one position to another with a magnetic field of 5.0x10-4 t. what current must a wire carry if it is to produce a 5.0x10-4 t field at 0.50m? i = ? ka

1.25 kA

Explanation:

The magnitude of the magnetic field produced by a current-carrying wire is given by:

where

is the vacuum permeability

is the current in the wire

r is the distance from the wire at which the field is calculated

In this problem, we have:

is the intensity of the magnetic field

is the distance from the wire

Re-arranging the equation, we can find the intensity of the current in the wire:

. west

can be answered using momentum.

momentum = p

p1= mass1 * velocity1

p1 = p2

therefore

p1 = 6kg * 4m/s

p1 = 24kgm/s

p2=m2 * v2

24 kgm/s = 7kg * v2

v2 = 24 kgm/s / 7kg

v2= 3.42 m/s