A250-kg crate is on a rough ramp, inclined at 30° above the horizontal. the coefficient of kinetic friction between the crate and ramp is 0.22. a horizontal force of 5000 n is applied to the crate, pushing it up the ramp. what is the acceleration of the crate?

The acceleration of crate is .

Explanation:

Given data:

Mass of crate is, .

Angle of inclination is, .

The coefficient of kinetic friction between crate and ramp is, .

Magnitude of horizontal force is, .

In an inclined plane, the net force acting on the crate is given as,

Here, a is the linear acceleration and g is the gravitational acceleration.

f is the frictional force in an inclined plane and its value is,

N is the normal reaction acting on crate in an inclined plane and its value is,

Then frictional force is,

Then acceleration is,

Thus, the acceleration of crate is .

For more details, refer the link:

link

Explanation:

We are given that

Mass of crate=250 kg

Coefficient of kinetic friction between the crate and ramp=0.22

Horizontal force applied on the crate=5000 N

We have to find the acceleration of the crate.

The normal force acting on the crate

The friction force acting against the motion of crate=

According to newton's second law, the net force accelerating the crate

Hence, the acceleration of the crate=

force is mass*acceleration.

we have a very small mass: 11.4*0.001 kg

if we want 0.035n of force, we need an acceleration:

0.035 = 11.4*0.001*a

a = 0.035/(11.4*0.001) m/s^2

graph slopes whilst gas cools, then it is flat whilst conensation to liquid happens, the coolong liquid then graphs as a slope when it solidifies graph is flat

latent heat