Two children are riding on the edge of a merry-go-round that has a mass of 100.kg and radius of 1.60m and is rotating at 20.0rpm (disc). ignore friction. the children have masses of 22.0kg and 28.0kg and are seated on the outside (simple pendulum). if both children move to half the radius (0.8m) what is the new rotational speed?

Here since both children and merry go round is our system and there is no torque acting on this system

So we will use angular momentum conservation in this

now here we have

Now when children come to the position of half radius

then we will have

now from above equation we have

the plateau is likely to turn into a desert do to corrosion.

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer