The lever in the figure below accomplishes 5.0 newtons-meters of work raising a 25 newton weight. how far, in meters is the weight raised?

The simple definition of work is the product of the force applied to the object and the displacement:

W = Fd

W is the work, F is the applied force, and d is the displacement.

Givens:

W = 5.0N-m

F = 25N (the applied force must be at least equal to the weight to lift it)

Plug in the given values and solve for d:

5.0 = 25d

d = 0.20m

be subject to a force andchange its motion

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft