Two flat conductors are placed with their inner faces separated by 9mm. if the surface charge density on inner face a is 69 pc/m^2 and on inner face b is -69 pc/m^2 calculate the electric potential difference using epsilon naught value of 8.85419x10^-12 c^2/nm^2. answer in units of v.

0.07 V

Explanation:

The electric field between two parallel plates is uniform, and its magnitude is given by

where

is the magnitude of the charge density on each face

is the vacuum permittivity

In this problem, we have

So, the electric field is

So now we can calculate the potential difference between the two plates, given by:

where is the distance between the two plates. Substituting, we find

the area between the graph and the t axis