Early one february morning you go outside to build a snow man. you make a 3.2kg snowball and lift it to a height of 1.2m, then carry it 25m on level ground with a force of 1.0n to your snowman and then lift it up the rest of the way to set as the head of a 2.3m snowman. how much work do you do on the snowball as you transport it and position it on your masterpiece?

First the amount of work done in lifting up the snow ball to a height of 1.2m is equal to the potential energy of the ball after the lift.

Therefore mass× gravitational pull×height will give us the work done

=3.2kg ×9.8N/kg×1.2m

=37.632J

then, the work done over the 25m distance if found by the following formula: work done=force×distance

=1.0N×25m

=25J

On reaching the headless snowman you have to lift the ball a further 1.1m to place it as the head 2.3m high.

therefore this will be a change in potential energy which is equal to work done in lifting the ball the additional 1.1m

=m×g×h

=3.2kg×9.8N/kg×1.1m

=34.496J

To get the total we add the amount of work done in the various instances.

from

explanation:

wind is defined by the direction it blows from.   for example, a wind blowing from north to south is called a northerly wind.

what was the acceleration of the 2 kg cart?

⇒ 16.0 cm/s2

what was the acceleration of the 4 kg cart?

⇒ 8.1 cm/s2

what was the acceleration of the 6 kg cart?

⇒ 5.3 cm/s2