Aforce of 200 n is applied to an input piston of cross-sectional area 2 sq. cm pushing it downward 2.8 cm. how far does the output piston of cross-sectional area 12 sq. cm move upward? show all work.

0.46 cm upward

Explanation:

Given that,

Input force

Input piston of cross- sectional area

Output force =  

Output piston of cross-section area

For  output force,

Input pressure = Output pressure

For upward displacement,

The work done

Hence, the piston moves 0.46 cm upward.

thermal energy is the answer