Suppose a piece of dust finds itself on a cd. if the spin rate of the cd is 355 rpm, and the piece of dust is 4.5 cm from the center, what is the total distance (in m) traveled by the dust in 8 minutes? (ignore accelerations due to getting the cd rotating.) m

we know that 1 rpm =

w = angular speed of cd  = 355 rpm =   = 37.2

r = distance from the center for piece of dust = 4.5 cm = 0.045 m

v = speed of motion for piece of dust = ?

Speed is given as

v = r w

inserting the values

v = (0.045) (37.2)

v = 1.67

t = time of travel for piece of dust = 8 min = 8 x 60 sec = 480 sec        (Since 1 min = 60 s)

d = distance traveled by piece of dust = ?

Distance traveled by piece of dust  is given as

d = v t

inserting the values

d = (1.67) (480)

d = 801.6 m

i think it’s a. this is because if they measured the mass of something with a mass of 150g, then their final answer would have to be approximately 150g. though all of their answers are almost 150, rosa and tran have the closest answers (or the exact answer) to the accurate one.

a charge 3q is at the origin, and a charge −2q is on the positive x axis at x=a. part a where on the x-axis would you place a third charge so it would experience no net electric force? enter an expression for the exact answer, which will involve a square-root sign. (do not enter an approximate decimal answer.)