Physics, 24.06.2019 08:30 smarty5187

A14 kg rock starting from rest free falls through a distance of 5.0 m with no air resistance. find the momentum change of the rock caused by its fall and the resulting change in the magnitude of earths velocity. earth mass is 6.0 * 10^24 kg. show your work assuming the rock earth system is closed.

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Answer from: tousif2663

Use the equation p = mv

P - Momentum : We need to find out

M - Mass : 14 kg

V - Velocity : ?

Sorry this wasn't much help, you should probably report me, but i tried my best to help you out :/

Answer from: shadowsnake

$2.3*10^{-23} m/s$

Explanation:

Momentum (p) is defined as the product of the mass (m) and velocity (v) of an object:

p=mv

There are different types of momentum. Linear momentum (caused by the linear motion of te rock) and angular momentum (caused by the angular velocity of the earth).

Initial momentum of the falling rock equals zero, because its initial velocity is zero. To find the momentum change, we need its final value, for which we need its final velocity.

The kinematic formula, which relates final velocity (v), initial velocity (v0), acceleration (a) and falling distance (h) is:

$v^{2}=v_{0} +2ah$

In this case:

v^2=0+2(9.8m/s^2)(5.0m)=98m^2/s^2

$v=\sqrt{98m^2/s^2}$

v=9.9m/s

Now, the change in momentum (dp) of the rock is simply is simply:

$dp=m*v-m*v_{0}=m(v-v_{0})$

dp=14kg(9.9m/s-0m/s)=139kg*m/s

For closed systems (like this earth-rock system), momentum is conserved. It means that a change in rock's momentum equals to an opposite but in the same magnitude momentum change of the earth. The initial momentum of the earth is also equal to zero. Matching changes in momentum:

$dP_{rock}=dP_{earth}\\14kg*9.9m/s=6.0*10^{24} kg*v$

Solving for v:

$v=2.3*10^{-23} m/s$

The, the change in earth's speed magnitude is 2.3*10^-23m/s

Answer from: Quest

You would need to take a picture so i can see

Answer from: Quest

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j

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A14 kg rock starting from rest free falls through a distance of 5.0 m with no air resistance. find t...

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