A0.600 m long pendulum is used to determine the acceleration due to gravity on a distant plane. if 20 oscillations are completed in 35.5 s, the acceleration would be

7.50 m/s^2

Explanation:

The period of a pendulum is given by:

(1)

where

L = 0.600 m is the length of the pendulum

g = ? is the acceleration due to gravity

In this problem, we can find the period T. In fact, the frequency is equal to the number of oscillations per second, so:

And the period is the reciprocal of the frequency:

And by using this into eq.(1), we can find the value of g:

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