Saki is ice-skating to the left with a velocity of 5\,\dfrac{\text{m}}{\text{s}}5 s m . a steady breeze starts blowing, causing saki to accelerate leftward at a constant rate of 1.5\,\dfrac{\text{m}}{\text{s}^2}1. 5 s 2 m . after 6\,\text s6s, what is saki's velocity? answer using a coordinate system where rightward is positive.

-14 m/s

Explanation:

Saki's initial velocity is:

where we put a negative sign because the problem tells us to use a coordinte system in which rightward is positive, while Saki's initial velocity is towards the left.

Saki's acceleration due to the breeze is:

Where again, we put a negative sign since the acceleration is leftward.

In order to find Saki's velocity after t = 6 s, we can use the following equation:

And substituting all the numbers, we get

and the negative sign means the new velocity is leftwards.

answer would be d.) i hope this

explanation:

the answer would be 32*f