Aball dropped from a bridge takes three seconds to reach the water below how far is the bridge above the water?

Given that:

Ball dropped from a bridge at the rate of 3 seconds

Determine the height of fall (S) = ?

      As we know that, S = ut + 1/2 ×a.t²

                          u =initial velocity = 0

                          a= g =9.81 m/s  (since free fall)

                            S = 0+ 1/2 × 9.81 × 3²

                          S = 44.145 m

44.145 m far is the bridge from water