Aframe hanging on a wall is held by two cables. the tension in each cable is 30 n, and the cables make an angle of 45° with the horizontal, as shown in the picture. what is the weight of the frame? a) 10.2 n b) 21.2 n c) 32.4 n d) 42.4 n

(D) 42.4N

Explanation:

Since the frame is at rest, the net force acting on it must be 0. There are three forces acting on it: the gravity and the opposing forces of the two cables.

Since the gravity is a vertical force, we are only interested in the vertical components of the remaining forces. The net force equation is

F_net = 0 = F_g -2 * F_y

The vertical force of one cable (using the information in the drawing) is:

F_y = 30N * sin 45 deg = 21.21N

Now the weight can be determined:

0 = F_g - 2 * F_y

F_g= 2 * F_y = 2 * 21.21N = 42.4N

The weight of the frame is about 42.4N.

Vector:T₁+T₂+F=0 , you put the vectors where you need, on the site I'm not going to put them

We design the relationship on the vertical axis Oy:

T₁sinα+T₂sinα=0

T₁=T₂=>2Tsinα=0

We design the relationship on the horizontal axis Ox :

2Tcosα-F=0=>F=2Tcosα=2*30*√2/2=30√2=42.4 N

The right answer is D

the answer would be 32*f

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