Adog pushes a toy horizontally on a frictionless floor with a net force of 2.0\, \text n2.0n for 1.0\,\text m1.0m. how much kinetic energy does the toy gain?

2.0 J

Explanation:

Since the surface is frictionless, we can solve the problem by using the work-energy theorem, which states that the work done on the toy is equal to the kinetic energy gained by the toy:

where

W is the work done on the toy

is the kinetic energy gained by the toy

The work done can be calculated as the product between the force applied on the toy and its displacement, so:

Therefore, according to the work-energy theorem, the toy has gained 2.0 J of kinetic energy.

the answer for apex is the lowest

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.