Physics, 28.06.2019 00:00 fgcherubin
When the speed of the bottle is 2 m/s, the ke is kg m2/s2. when the speed of the bottle is 3 m/s, the ke is kg m2/s2. when the speed of the bottle is 4 m/s, the ke is kg m2/s2. when the speed of the bottle is 5 m/s, the ke is kg m2/s2. when the speed of the bottle is 6 m/s, the ke is kg m2/s2. instructions in this part of the experiment, you will be changing the speed of the bottle by dropping it from different heights. you will use the same mass, 0.250 kg, for each trial, so record this mass in table b for each velocity. then, calculate the expected kinetic energy (ke) at each velocity. use the formula ke = mv2, where m is the mass and v is the speed. record your calculations in table b of your student guide.
Answers: 2
Physics, 22.06.2019 00:00
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Physics, 22.06.2019 00:30
Consider an ordinary, helium-filled party balloon with a volume of 2.2 ft3. the lifting force on the balloon due to the outside air is the net resultant of the pressure distribution exerted on the exterior surface of the balloon. using this fact, we can derive archimedes’ principle, namely that the upward force on the balloon is equal to the weight of the air displaced by the balloon. assuming that the balloon is at sea level, where the air density is 0.002377 slug/ft3, calculate the maximum weight that can be lifted by the balloon. note: the molecular weight of air is 28.8 and that of helium is 4.
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Physics, 22.06.2019 14:00
Ascientific blank must be testable and capable of being proven false?
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When the speed of the bottle is 2 m/s, the ke is kg m2/s2. when the speed of the bottle is 3 m/s, th...
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