A10kg sphere hits a stationary 8kg sphere. after the collision the 8kg sphere moves off in the positive direction at 4m/s. if the 10kg sphere was originally moving at 10m/s, what is its velocity after the collision?

M = mass of the first sphere = 10 kg

m = mass of the second sphere = 8 kg

V = initial velocity of the first sphere before collision = 10 m/s

v = initial velocity of the second sphere before collision = 0 m/s

V' = final velocity of the first sphere after collision = ?

v' = final velocity of the second sphere after collision = 4 m/s

using conservation of momentum

M V + m v = M V' + m v'

(10) (10) + (8) (0) = (10) V' + (8) (4)

100 = (10) V' + 32

(10) V' = 68

V' = 6.8 m/s

im srry but ur wrong the answer is d a smooth rock, some red dirt, and an empty bird's nest.

force required to detach it is given by

charges are taken to be fundamental charge

now we have

so above is the minimum distance at which it will detach