Aball having a mass of 500ghits wall with a 10m/s velocity. wall applies 4000 n force to the ball and it turns back with 8m/s velocity . what it the ball- wall contact ?

As per Newton's II law we know that

now here we will have

we know that

m = 500 g = 0.5 kg

F = 4000 N

now from above equation we will have

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer