Abowling bowl is thrown off the top of a building. determine distance the ball has fallen after falling for 3.0 s. remember, the gravitational acceleration (g) is 9.8 m/s2. (hint: d = ½gt2)

consider the motion of the bowling ball along the vertical direction after it is thrown off.

assuming down direction as positive.

Y = vertical displacement of the bowling ball = distance traveled downward = d

a = acceleration of the ball = acceleration due to gravity = 9.8 m/s²

t = time of travel = 3.0 s

v₀ = initial velocity of the ball along the vertical direction = 0 m/s

using the equation

Y = v₀ t + (0.5) a t²

d = 0 (3.0) + (0.5) (9.8) (3.0)²

d = (0.5) (9.8) (9.0)

d = 44.1 m

a and c

c is 100% but i am confused in a

speed of light in vacuum is 300,000 km/s

speed of light in other mediums is given by the expression v = c/n, where c is the speed of light in vacuum and n is the refractive index of medium.

for the first medium v = 200,000 km/s

  so, refractive index of medium = 300000/200000 = 1.5

    1.5 refractive index is usually for glass. so first medium is glass.

for the second medium v = 250,00 km/s

so, refractive index of medium = 300000/250000 = 1.2

    1.2 refractive index is usually for water. so second medium is water.

for the third medium v = 0 km/s

so, refractive index of medium = 300000/0 = ∞

    ∞ refractive index is usually for opaque mediums. so third medium is opaque medium.