Ajet fighter performs a horizontal circular turn of radius 1410. the jet is travelling at a constant speed of 235 m/s and has mass 14332. what is the magnitude of the centripetal force experienced by the pilot?

The pilot experiences a centripetal force of 561336.66 N

The formula for calculating centripetal force is

F = mv² / r

We are given with

F = ?

m = 14332

v = 235

r = 1410

So putting the values in the equation

F = (14332) x (235)² / 1410

F = 561336.66 Newtons

i think it is 561336.66N because i used the formula f=mv^2/r

so if F=?

your mass= m    m= 14332

your speed=v     v= 235

your radius of the circular turn=r    r= 1410

so F= (14332)*(235)^2/1410=

=561336.66N

in simple terms, the principle states that the buoyancy force on an object is equal to the weight of the fluid displaced by the object, or the density of the fluid multiplied by the submerged volume times the gravitational acceleration, g. this is also known as upthrust.