Aball with a mass of 0.50 kilograms is moving at a speed of 1.8 meters/second along the positive x-axis. it collides with another ball of the same mass travelling at a speed of 2.0 meters/second toward the positive y-axis. both balls then start moving together. what is the magnitude of the resultant momentum before collision?

1.35 kg m/s

Explanation:

The law of conservation of momentum states that the total momentum before and after the collision is conserved, therefore:

we can calculate the total momentum before the collision, , since we know the masses and the initial velocities of the two balls.

The momentum along the x-axis is given only by the first ball, since the second one is moving on the y-axis:

The momentum along the y-axis is given only by the second ball, since the first one is moving on the x-axis:

So, the magnitude of the resultant momentum is

And since the total momentum after the collision is equal to the momentum before the collision,

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂