Aball rolls with a speed of 2.0m/s across a level table that is 1.0m above the floor. upon reaching the edge of the table it follows a parabolic path to the floor. how far along the floor is the landing spot from the table?

The distance covered by the ball is 0.9 m.

Explanation:

Given that,

Speed of ball = 2.0 m/s

Distance = 1.0 m

We need to calculate the time

Using equation of motion

Here, u = initial velocity=0

Where, h = distance

g = acceleration due to gravity

t = time

Put the value into the formula

We need to calculate the distance of the ball

Using formula of velocity

Hence, The distance covered by the ball is 0.9 m.

he kicked it 10 feet straight up into the air? i think this works.

ingenuity says that the answer is 2.7 m.