If a ball is launched upward with a vertical velocity of 50 m/s and a horizontal velocity of 10 m/s, what will the vertical displacement be 5 seconds later?

The vertical displacement will be 127.5 meters

Step by step:

Since the question asks for the vertical displacement only, it is sufficient to limit our calculation to the vertical components of the problem.

We choose to measure the displacement on a vertical axis d with an initial coordinate 0 coinciding with the launch of the ball. There is an initial horizontal velocity v_0 of 50 m/s and the gravitational deceleration g acting in the direction opposite to the initial velocity. The formula for displacement of a body subject to an deceleration with an initial velocity (at time t=5 seconds) is:

After 5 seconds of the launch, the ball will be at the point 127.5 meters from the origin on the vertical axis (vertical displacement)

double the distance = divide strength by 4

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