A0.075 kg ball in a kinetic sculpture moves at a constant speed along a motorized vertical conveyor belt. the ball rises 1.32 m above the ground. a constant frictional force of 0.350 n acts in the direction opposite the conveyor belt's motion. what is the net work done on the ball?

0.51 J

Explanation:

The work done on the ball is equal to the sum of two terms:

- the work done in lifting the ball by 1.32 m

- the work done by the frictional force of 0.350 N that acts opposite to the motion; this work is negative, since the force acts in the opposite direction to the motion of the ball.

In formulas, the net work done is:

where

m = 0.075 kg is the ball's mass

g = 9.8 m/s^2 is the gravitational acceleration

h = 1.32 m is the height throug which the ball has been moved

Ff = 0.350 N is the frictional force

Substituting, we find

c. 7/3

step-by-step explanation:

a rational number is like pi- it is a repeating decimal.

a. is -1.8

b. 2.236068

c. 2.3333333333333333333

d.   is 3

i hope that ! =)