Astationary 15 kg object is located in a table near the surface of the earth. the coefficient of static friction between the surfaces is 0.40 and the coefficient of kinetic friction is 0.25. a horizontal force of 20 n is applied to the object. determine the acceleration of the object.

The applied force is  then the object will not move due to this force and it will remain at rest always  due to this applied force.

Explanation:

Given: A stationary object is located in a table near the surface of the earth. The coefficient of static friction between the surfaces is and the coefficient of kinetic friction is .

Weight of the object is .

The maximum static friction acting on the object will be

Substiuting all the values:

Here, force of static friction is . it means that if applied force is less than or equal to , then the object will remain stationary as friction can balance the external force upto this limit of external force.

Therefore, the applied force is  then the object will not move due to this force and it will remain at rest always  due to this applied force.

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maximum static friction acting on the object will be

plug in all values

So here it means that if applied force is less than or equal to 58.8 N then the object will remain stationary as friction can balance the external force upto this limit of external force

So here it is given that applied force is 20 N

so here object will not move due to this force and it will remain at rest always

due to this applied force

d. platinum would have the greatest temperature increase because it has the lowest specific heat.

energy stored in the capacitor= 9.72 x 10⁻⁴ j

explanation:

the energy stored in the capacitor is given by

e= 1/2 c v²

e= energy stored

c= capacitance= 1.5 µc= 1.5 x 10⁻⁶f

v= potential difference=36 v

so energy stored= e= 1/2 (1.5 x 10⁻⁶) (36)²

energy stored= 9.72 x 10⁻⁴j