When a mass of 5 kg hangs from a vertical wire of length 2 m, waves travel on this wire with a speed of 10 m/s. what will the speed of these waves be, if the mass is doubled without stretching the wire? 14 m/s 20 m/s 5.0 m/s 12 m/s

The speed of these waves will be 14 m/s

Let's recall the speed of wave formula as follows:

where:

c = speed of wave ( m/s )

λ = wavelength ( m )

f = frequency of wave ( Hz )

where:

v = speed of wave on string ( m/s )

T = tension in the string ( N )

μ = linear density ( kg/m )

Let us now tackle the problem!

Given:

initial mass = m₁ = 5 kg

length of vertical wire = L = 2 m

initial speed of wave = v₁ = 10 m/s

final mass = m₂ = 2m₁ = 2(5) = 10 kg

Asked:

final speed of wave = v₂ = ?

Solution:

Grade: High School

Subject: Physics

Chapter: Wave

its a 5.5 n

glad that