Alarge cylindrical water tank 11.5 m in diameter and 13.5 m tall is supported with its base 8.75 m above the ground by a stand as shown in the figure. the water level in the tank is 10.6 m deep, and the density of the water in the tank is 1.00 g/cm3. a very small hole is formed at the base of the vertical wall of the tank, and water is squirting out of this hole horizontally. when this water hits the ground, how far has it traveled horizontally from the hole, assuming no air resistance?

by Bernuolli's equation of energy of fluid we can find the velocity of water coming out of the hole

here we know that density of the water is

atmospheric pressure is given as

height of the water level from the hole is given as h = 10.6 m

now from above equation we will have

by solving above equation we will have

now with this speed water will eject horizontally from the hole

now its height is given as 8.75 m from the ground so time taken by the water to reach the ground is

so it will take 1.34 s to hit the ground

So in this time the horizontal distance where it will hit is given as

So here it will hit at distance of 19.2 m from the base of the container

a

explanation:

no diagram was provided, but i'm guessing it's the one i've attached to my answer.

here, a mechanical force turns the rod.   this generates an electric current in the coil, which powers the bulb.

answer( sicar );