The driver of a car going 86.0 km/h suddenly sees the lights of a barrier 44.0 m ahead. it takes the driver 0.75 s to apply the brakes, and the average acceleration during braking is -10.0 m/s2. (a) determine whether the car hits the barrier. (b) what is the maximum speed at which the car could be moving and not hit the barrier 44.0 m ahead? assume that the acceleration doesn't change.

Part a

NO

We need to calculate the distance traveled once the brakes are applied. Then we would compare the distance traveled and distance of the barrier.

Using the second equation of motion:

where s is the distance traveled, u is the initial velocity, t is the time taken and a is the acceleration.

It is given that, u=86.0 km/h=23.9 m/s, t=0.75 s,

Since there is sufficient distance between position where car would stop and the barrier, the car would not hit it.

Part b

29.6 m/s

The maximum distance that car can travel is

The acceleration is same,

The final velocity, v=0

Using the third equation of motion, we can find the maximum initial velocity for car to not hit the barrier:

Hence, the maximum speed at which car can travel and not hit the barrier is 29.6 m/s.

graph slopes whilst gas cools, then it is flat whilst conensation to liquid happens, the coolong liquid then graphs as a slope when it solidifies graph is flat

latent heat

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards