Arock is thrown upward with an initial velocity of 9.6m/s to what hight does it rise and how long does it take to reach that high

Given:

u(initial velocity):9.6 m/s

at the maximum height final velocity =0

The acceleration acting on the body is gravity as it is free falling object

=-9.8m/s^2

Now we know that

v^2-u^2 = 2as

Where v is the final velocity measured in m/s

u is the initial velocity which is measured in m/s

a is the acceleration measured in m/s^2

s is the distance traveled by the rock in this case it is considered as the height

Substituting these values we get

0-9.6= 2 x -9.8 x s

s= 0.49 m

Consider t as the time taken for the rock to travel

v=u+at

0=9.6 -9.8t

t=0.98sec

when earth is in rotational motion around the sun,it displaces from its place.

when a ball is placed on an inclined surface it does both the rotational and circular motion.

explanation:

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