Asample of a gas in a rigid container has an initial pressure of 5 atm at a temperature of 254.5 k. the temperature is decreased to 101.8 k what is the new pressures ? show work.

The gas is in a rigid container: this means that its volume remains constant. Therefore, we can use Gay-Lussac law, which states that for a gas at constant volume, the pressure is directly proportional to the temperature. The law can be written as follows:

Where P1=5 atm is the initial pressure, T1=254.5 K is the initial temperature, P2 is the new pressure and T2=101.8 K is the new temperature. Re-arranging the equation and using the data of the problem, we can find P2:

So, the new pressure is 2 atm.

the current is 0.6

voltage ÷ resistance = current

so 12 ÷ 20 = 0.6

when heated, the valance electrons increased their speed and transferred the heat from electron to electron.   i just took the test.