What will the stopping distance be for a 2,000-kg car if -2,000 n of force are applied when the car is traveling 20 m/s? a. 400,000 m b. 200 m c. 100 m d. 20 m

Stopping distance, s = 200 meters

Explanation:

Mass of the car, m = 2000 kg

Force acting in the car, F = -2000 N

Initial speed of car, u = 20 m/s

Finally, it stops, v = 0          

Using second equation of motion as :      

Let s is the stopping distance. Now using third equation of motion as :

s = 200 meters

So, the stopping distance of the car is 200 meters. Hence, this is the required solution.

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