Aflower pot is theown out of a window with a horizontal velocity of 8 m/s. if the window is 1.5 m off the ground, how far from the window does it land?

3.26m

Explanation:

Using one of the equation of motion to get the distance of the pot from the window and the ground;

v² = u²+2as where

v is the final velocity = 8m/s

u is the initial velocity = 0m/s

a =+g = acceleration due to gravity (this acceleration is positive since the body is falling downwards)

g = 9.81m/s

s is the distance between the object and the window from which it dropped.

Substituting this values to get the distance s we have;

8² = 0²+2(9.81)s

64 = 19.62s

s = 64/19.62

S = 3.26m

the maxium height is 34m/s

there are no components of a physical goal mentioned on the list of choices that you've provided.