Arocket ship starts from rest and turns on its forward booster rockets, causing it to have a constant acceleration of 4 m/s^2 rightward. after 3s, what will be the velocity of the rocket ship? answer using a coordinate system where rightward is positive.

here rocket starts from rest

It turns the booster and continue with constant acceleration

now in order to find the final velocity we can use kinematics equation

here we know that

t = 3 s

now plug in all data in above equation

so the rocket will move rightwards with speed 12 m/s after 3 s of boosters

because it says use -2,0,and 2 for x, we can plug those numbers into the equation. y/4=3/4(-2)+2   y/4= -1 1/2 +2 now to get x by itself, we can multiply each side by 4. y=-6+8 which equals y=2 when x=-2. now you can do the same thing with 0 and 2 as x. you get y=8 when x=0 and y=14 when x=2.

x   |   y

-2 |   2

0   |   8

2   |   14

answer: question1

1,000 tons

question2

3: 8

question 3

store d

step-by-step explanation: