Physics, 08.07.2019 02:30 AM28

Acar is driving at a velocity of 24 m/s. if its brakes can supply an acceleration of -5.0 m/s2, how much time will be required to bring the car to a stop?

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In equation form it reads: 0=24-5x
You can isolate the variable by subtracting 24 from both sides to get -24=5x.
Now all that has to be done is divide both sides by -5, which will result in -4.8=x

Answer from: lala1794

Time, t = 4.8 seconds

Explanation:

Given that,

Initial velocity of the car, u = 24 m/s

Acceleration of the car, $a=-5\ m/s^2$

When the brakes are applied, v = 0

Let t is the time required by the car to stop it. It can be calculated using the formula of the acceleration as :

$a=\dfrac{v-u}{t}$

$t=\dfrac{v-u}{a}$

$t=\dfrac{0-24}{-5}$

t = 4.8 seconds

So, the time required to bring the car to a stop is 4.8 seconds. Hence, this is the required solution.

Answer from: Quest

as technology advances, new experiments often expose problems in accepted theories. c

hope i

-lavira: )

Answer from: Quest

force is based upon mass and acceleration.the statement is not always true.

it can be explained from newton's second law of motion.

as per newton's second law of motion the rate of change of momentum is directly proportional to the applied force and takes place along the direction of force.

mathematically it can be written as -

$f\alpha \frac{dp}{dt}$

⇒ $f= k \frac{dp}{dt}$

here k is the proportionality constant whose value is 1.

$f=\frac{dp}{dt}$

$f= \frac{d[mv]}{dt}$

$f= m\frac{dv}{dt} +v\frac{dm}{dt}$

$f=ma+v\frac{dm}{dt}$ [a is the acceleration=dv/dt]

hence we see that force not only depends on mass and acceleration but also on velocity and rate of change of mass. force f will depend on mass and acceleration only when mass is constant.

hence the statement that force is based upon mass and acceleration is false.

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Acar is driving at a velocity of 24 m/s. if its brakes can supply an acceleration of -5.0 m/s2, how...

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