Arocket starts from rest and moves upward from the surface of the earth. for the first 10.0 s of its motion, the vertical acceleration of the rocket is given by ay=(2.60m/s3)t, where the +y-direction is upward.

acceleration of rocket is given here as

now we know that

now integrating both sides

here since its given that rocket will accelerate for t = 10 s

so here we have

so after t = 10 s the speed of rocket will be 130 m/s upwards

can somebody give me the answer so i can graduate