Ccording to coulomb's law, which pair of charged particles has the lowest potential energy? according to coulomb's law, which pair of charged particles has the lowest potential energy? a particle with a 1− charge separated by 100 pm from a particle with a 3+ charge. a particle with a 1− charge separated by 100 pm from a particle with a 2+ charge. a particle with a 1− charge separated by 200 pm from a particle with a 1+ charge.

The electrostatic potential energy of a particle with a 1− charge separated by 200 pm from a particle with a 1+ charge.

Explanation:  

The formula for the electrostatic potential energy is as follows;

Here, U is the potential energy, are the charges and r is the distance between them.

Here,

is the absolute permittivity of free space.

Calculate the electrostatic potential energy of a particle with a 1− charge separated by 100 pm from a particle with a 3+ charge.  

Put q_{1}=-1, q_{2}=+3,k= and r=100 pm.

Calculate the electrostatic potential energy of a particle with a 1− charge separated by 100 pm from a particle with a 2+ charge.

Put q_{1}=-1, q_{2}=+2 and r=100 pm.

Calculate the electrostatic potential energy of a particle with a 1− charge separated by 200 pm from a particle with a 1+ charge.

Put q_{1}=-1, q_{2}=+1 and r=200 pm.

Therefore, the electrostatic potential energy of a particle with a 1− charge separated by 200 pm from a particle with a 1+ charge.

0.93xc=0.93x3x10^8m/s

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