Acharge of +1 coulomb is place at the 0 cm mark of a meter stick. a charge of +4 coulombs is placed at the 100 cm mark of the same meter stick. where should a proton be placed on the meter stick so that the net force on it due to the two charges is 0? answer in units of cm

Explanation:

Let the proton is placed at the position x = x between two given charges

Now the force on this proton is zero due to two given charges

so we will have

now plug in all data

square root both sides

given data:

determine the horse power (h.p) = ?

force applied to move the box(f) = 10 pounds,

box lifted from a distance         (d) = 3 feet

time taken to lift                         (t) = 10 sec,

the horse power is defined as amount of work required to move a load. the horse power is equal to 550 foot-pound per second

                  1 h.p   = 550 foot-pound/second

it can also be defined as the the load that need to be move a body for certain distance in a certain amount of time.

mathematically,

                      h.p = (force × distance)/ time

                            = (10 × 3)/ 10

                            = 30/10

                            = 3 foot -pound/sec

hence, the horse power is needed to move the box is 3 foot-pound/second

important note: 1 h.p = 550 foot-pound/second = 746 watts

(75°f − 32) × 5/9 = 23.889°c