What is the acceleration of a wagon of mass 20kg if a horizontal force of 64 is applied to it

Here we have to calculate the acceleration of the wagon.

as per the question the mass of the wagon is given as 20 kg

the horizontal force that is applied on the body is 64 newton.

as the perfect unit of the fore is not mentioned it may be 64N or 64 dyne or 64 kgf.

as per Newton's second law of motion we know that the rate of change of momentum is the applied force.from the quantitative definition of Newton's second law we know that applied force is equal to the product of mass and acceleration.

hence

let F= 64 N,then

                                   a=3.2 m/s^2

if F=64kgf=64×9.8 N,then

                                                  =31.36 m/s^2

if F =64 dyne ,the acceleration is found to be 0.0032 cm/s^2 [ans]

i don't know that i agree with that but what's the question ?

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s