Askier is gliding along at 3.0 m/s on horizontal, frictionless snow. he suddenly starts down a 10" incline. his speed at the bottom is 15 m/s. a. what is the length of the incline? b. how long does it take him to reach the bottom?

The length of the inclined plane is 63.53 m and the time taken by the skier to cover the distance is 7.0588 sec.

Given to us

Velocity, u = 3.0 m/s

Angle of Inclination = 10"

Velocity of skier at the bottom, v = 15 m/s

We know that acceleration of the skier on the inclined plane can be given as,

a = g sin(θ)

a = g sin(10)

a= 9.81 x 0.1736

a = 1.70 m/sec²

We know that according to the third equation of motion

Substitute the values,

Using the first equation of motion,

Hence, the length of the inclined plane is 63.53 m and the time taken by the skier to cover the distance is 7.0588 sec.

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acceleration of the skier on the inclined plane is given by

now by equation of kinematics

so the length of inclined plane will be 63.53 m

Part b)

Time to reach the bottom will be given by

so it will take 7.06 s to reach the bottom

wavelegth as in spectrum red oygbiv

the ima (higher than 1m) will be greater than the ima with the height of 1m.