You're driving down the highway late one night at 22 m/s when a deer steps onto the road 38 m in front of you. your reaction time before stepping on the brakes is 0.50 s , and the maximum deceleration of your car is 10 m/s2 .

speed of the car is given on the road

reaction time is given as

now we can find the distance that it will move during this reaction time

now the deceleration of the car is 10 m/s^2

so the distance that it will move before stop is given by

so the total distance that it require to stop is given as

while the deer is standing at distance 38 m

so the car will stop 2.8 m before the position of deer

acceleration = (change in speed) / (time for the change)

change in speed = (20-120)= -100 m/s.

1.5 min = 90 sec

acceleration = -100/90 = -1.11 m/s^2.

we don't care about the 150kg or the 2,500 meters. they don't make any difference.

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your answer is c! hope this : )