Acertain simple pendulum has a period on the earth of 1.70 s . what is its period on the surface of mars, where g=3.71m/s2?

The time period for the simple the simple pendulum on the earth is

The time period for the simple the simple pendulum on the mars is

Here, and are the time periods on the earth and mars respectively and  and   are the acceleration due to gravity on earth and mars respectively.

We can also write,

or

Given and

Therefore,

or

.

Thus, the time period on the surface of mars is 2.76 sec.

The period of simple pendulum on the surface of Mars is about 2.76 s

Simple Harmonic Motion is a motion where the magnitude of acceleration is directly proportional to the magnitude of the displacement but in the opposite direction.

The pulled and then released spring is one of the examples of Simple Harmonic Motion. We can use the following formula to find the period of this spring.

T = Periode of Spring ( second )

m = Load Mass ( kg )

k = Spring Constant ( N / m )

The pendulum which moves back and forth is also an example of Simple Harmonic Motion. We can use the following formula to find the period of this pendulum.

T = Periode of Pendulum ( second )

L = Length of Pendulum ( kg )

g = Gravitational Acceleration ( m/s² )

Let us now tackle the problem !

Given:

Period of the pendulum on the Earth = T_e = 1.70 s

Gravitational Acceleration of the Earth = g_e = 9.8 m/s²

Gravitational Acceleration of the Mars = g_m = 3.71 m/s²

Unknown:

Period of the pendulum on the Mars = T_m = ?

Solution:

Grade: High School

Subject: Physics

Chapter: Simple Harmonic Motion

Keywords: Simple , Harmonic , Motion , Pendulum , Spring , Period , Frequency

the answer is d. 4

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