How much work (in joules) is done in moving a charge of 2.5 μc a distance of 35 cm along an equipotential at 12 v? do not include units with your answer?

The work done for moving a charge is due to the change in potential between the points. That is the work done is given by the expression W = qΔV. Where q is the charge and ΔV is the change in potential between two points.

In case of equipotential lines the value of potential is same at all the points.

So the value of ΔV when moving along a equipotential line is zero.

So W = qΔV = q*0=0

So no work is needed to move charge along an equipotential line.

Work done = 0

it has to be b, about 97 percent.