Acheetah runs at a steady velocity of 60 km/h (16.7 m/s). over a period of 5.0s, the cheetah increases its pace to 95 km/h (26.4 m/s). what is the average acceleration of the cheetah over this period? must show work.

acceleration =( final velocity - initial velocity ) / total time taken

initial velocity of cheetah = 16.7 m/s

final velocity of cheetah = 26.4 m/s

time taken to change speed = 5 s

acceleration =( final velocity - initial velocity ) / total time taken

so acceleration = (26.4 - 16.7) / 5

acceleration = 9.7/5 = 1.94

the average acceleration of the cheetah over this period is 1.94 m/s²

  1.the balanced   chemical equation is as below

cu +   2 ag(no)₃ → cu(no₃)₂   +2 ag

2.the   much silver   produced   is   50.9 g

step 1: find the   moles of cu

moles =   mass÷   molar mass

  from periodic table the molar mass of cu = 63.5 g/mol

moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236   moles

step 2: use the mole ratio to determine the   moles of ag

from equation above   cu: ag   is 1: 2

therefore the moles of ag   =0.236   moles   x 2/1 =0.472   moles

step 3: find the mass   of ag

mass = moles x molar mass

from periodic table   the molar mass of ag =107.87 g/mol

mass   = 0.472   moles x 107.87 g/mol = 50.9 g

3.   the   much   silver   collected worth is   1.797 oz

  convert   50.9 g   to oz

that is   1 gram = 0.0353 oz

          50.9 grams =?   oz

by cross multiplication

={(50.9 grams x 0.0353 oz) / 1   gram}   =1.797 oz

i am pretty sure it is c because when people are closer together, they cannot move as freely. picture being in a mostly full elevator, for instance. the people are right next to you, and you can barely move.