Three forces act on an object. a 3 n force acts due east and a 8 n force acts due north. if the net force on the object is zero, what is the magnitude of the third force? "

The third force C is in the opposite direction of the sum of the first two forces, A+B, but the magnitude is the same as A+B  

Since A & B are at right angles we can just use Pythagoras and trig:  

A+B magnitude = sqrt(6^2 + 3^2) = 6.71  

A+B angle = arctan(6/3) deg north of east = 63.4 deg (first quadrant)

So C magnitude = 6.71 (same as A+B)  

[C angle = 63.4 deg south of west (third quadrant) = -180+63.4 deg polar = -116.6 deg

electromagnetic waves travel through space with vacuums. give me brainliest if right.

your answer is, orbit around the nucleus