The highest barrier that a projectile can clear is 12.2 m, when the projectile is launched at an angle of 13.0 ° above the horizontal. what is the projectile's launch speed?

consider the motion in vertical direction

v = initial velocity in the vertical direction = ?

v' = final velocity in the vertical direction at the highest point = 0 m/s

a = acceleration due to gravity = - 9.8 m/s²

h = maximum height = 12.2 m

Using the kinematics equation

v'² = v² + 2 a h

0² = v² + 2 (- 9.8) (12.2)

v = 15.5 m/s

let assume that velocity of launch be v₀

θ = angle of launch = 13

vertical component of the velocity of launch is given as

v = v₀ Sinθ

15.5 = v₀ Sin13

v₀ = 69 m/s

c. convergent boundary.

explanation:

i think it because equal matrices have equal dimensions, only square matrices can be symmetric. for all indices and . every square diagonal matrix is symmetric, since all off-diagonal elements are zero. in linear algebra, a real symmetric matrix represents a self-adjoint operator over a real inner product space.