If 40.0 kj of energy are absorbed by .500 kg of water 10 degrees c, what is the final temperature of the water?

To solve the problem, we must use the following equation:

where

Q is the amount of heat energy absorbed by the water

m is the mass of the water

Ti and Tf are the initial and final temperature

Cs is the specific heat capacity of the water

The data we have in this problem are:

Q=40.0 kJ

m=0.500 kg

Substituting the data into the equation and re-arranging it, we find

So the final temperature of the water will be 29.1 degrees.

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west