Three deer, a, b, and c, are grazing in a field. deer b is located 62m from deer a at an angle of 51° north of west. deer c is located 77° north of east relative to deer a. the distance between deer b and c is 95m. what is the distance between deer a and c?

Based on the data given, the distance between deer A and C is 119.6 m

Using the information provided, a triangle ABC is formed

Using sine rule to find the angle at B

C = sin¹ (c * Sin A/a)

C = sin¹ (62 * sin 52/95)

C = 31°

Therefore;

angle at B = 180 - (52 + 31)

angle at B = 97°

Using cosine rule to find side AC

b² = 95² + 62² - 2 * 95 * 62 * cos97

b = 119.6 m

Therefore, the distance between deer A and C is 119.6 m

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Set deer A's position to be the origin. Let be the distance from deer A to deer C. We're given that deer B is 95 m away from deer C, which means the length of the vector is 95 (or ). Then

if the person is shown to have +90n, then ans is -10n.

if the person is shown to have -90n, then ans is +10n.