Calculate the approximate volume of a uranium nucleus, 23592u. (you can ignore the mass defect in this calculation and simply take the mass of the nucleus to be equal to the sum of the masses of its nucleons.)

Radius of nuclei is given by formula

now we can say volume of the nuclei is given as

now the density is given as

density = mass / volume

mass of nuclei = mass of neutron + mass of protons

Now density is given as

here we know that

= 1.2 fm

So from above we can say that density of all nuclei is almost same.

acceleration = (change in speed) / (time for the change)

change in speed = (20-120)= -100 m/s.

1.5 min = 90 sec

acceleration = -100/90 = -1.11 m/s^2.

we don't care about the 150kg or the 2,500 meters. they don't make any difference.

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answer: 802.3 kilo joules of energy represents 191.75 kilo calorie of energy.

explanation:

energy released during combustion of one mole methane = 802.3 kilo joules

if 1 kilo joule = 0.239006   kilo calorie

then ,802.3 kilo joule will be = 802.30.239006 kilo calorie

802.3 kilo joule = 191.75 kilo calorie

hence, the energy in kilo calorie is 191.75 kilo calorie.