If the 140 g ball is moving horizontally at 25 m/s , and the catch is made when the ballplayer is at the highest point of his leap, what is his speed immediately after stopping the ball

(.140*25)+(75*0)= 3.5

3.5 = (.140 + 75)v

(3.5)/(.140 + 75) = v = .04657

which rounds up to .05 m/s

4.6 x 10(-2 power) m/s

Explanation:

Mastering Physics wants the answer like this.

increase masses, decrease separation

the answer is f1 and d2 because if you put equal force on those two points the beam would balance trust me on this